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# author : S. Mandalia
# s.p.mandalia@qmul.ac.uk
#
# date : March 17, 2018
"""
Useful functions for the BSM flavour ratio analysis
"""
from __future__ import absolute_import, division
import sys
import numpy as np
from scipy import linalg
MASS_EIGENVALUES = [7.40E-23, 2.515E-21]
"""SM mass eigenvalues"""
def angles_to_fr(src_angles):
"""Convert angular projection of the source flavour ratio back into the
flavour ratio.
Parameters
----------
src_angles : list, length = 2
sin(phi)^4 and cos(psi)^2
Returns
----------
flavour ratios (nue, numu, nutau)
Examples
----------
>>> print angles_to_fr((0.3, 0.4))
(0.38340579025361626, 0.16431676725154978, 0.45227744249483393)
"""
sphi4, c2psi = src_angles
psi = (0.5)*np.arccos(c2psi)
sphi2 = np.sqrt(sphi4)
cphi2 = 1. - sphi2
spsi2 = np.sin(psi)**2
cspi2 = 1. - spsi2
x = sphi2*cspi2
y = sphi2*spsi2
z = cphi2
return x, y, z
def angles_to_u(bsm_angles):
"""Convert angular projection of the mixing matrix elements back into the
mixing matrix elements.
Parameters
----------
bsm_angles : list, length = 4
sin(12)^2, cos(13)^4, sin(23)^2 and deltacp
Returns
----------
unitary numpy ndarray of shape (3, 3)
Examples
----------
>>> from fr import angles_to_u
>>> print angles_to_u((0.2, 0.3, 0.5, 1.5))
array([[ 0.66195018+0.j , 0.33097509+0.j , 0.04757188-0.6708311j ],
[-0.34631487-0.42427084j, 0.61741198-0.21213542j, 0.52331757+0.j ],
[ 0.28614067-0.42427084j, -0.64749908-0.21213542j, 0.52331757+0.j ]])
"""
s12_2, c13_4, s23_2, dcp = bsm_angles
dcp = np.complex128(dcp)
c12_2 = 1. - s12_2
c13_2 = np.sqrt(c13_4)
s13_2 = 1. - c13_2
c23_2 = 1. - s23_2
t12 = np.arcsin(np.sqrt(s12_2))
t13 = np.arccos(np.sqrt(c13_2))
t23 = np.arcsin(np.sqrt(s23_2))
c12 = np.cos(t12)
s12 = np.sin(t12)
c13 = np.cos(t13)
s13 = np.sin(t13)
c23 = np.cos(t23)
s23 = np.sin(t23)
p1 = np.array([[1 , 0 , 0] , [0 , c23 , s23] , [0 , -s23 , c23]] , dtype=np.complex128)
p2 = np.array([[c13 , 0 , s13*np.exp(-1j*dcp)] , [0 , 1 , 0] , [-s13*np.exp(1j*dcp) , 0 , c13]] , dtype=np.complex128)
p3 = np.array([[c12 , s12 , 0] , [-s12 , c12 , 0] , [0 , 0 , 1]] , dtype=np.complex128)
u = np.dot(np.dot(p1, p2), p3)
return u
def cardano_eqn(ham):
"""Diagonalise the effective Hamiltonian 3x3 matrix into the form
h_{eff} = UE_{eff}U^{dagger} using the procedure in PRD91, 052003 (2015).
Parameters
----------
ham : numpy ndarray of shape (3, 3)
sin(12)^2, cos(13)^4, sin(23)^2 and deltacp
Returns
----------
unitary numpy ndarray of shape (3, 3)
Examples
----------
>>> import numpy as np
>>> from fr import cardano_eqn
>>> ham = np.array(
>>> [[ 0.66195018+0.j , 0.33097509+0.j , 0.04757188-0.6708311j ],
>>> [-0.34631487-0.42427084j, 0.61741198-0.21213542j, 0.52331757+0.j ],
>>> [ 0.28614067-0.42427084j, -0.64749908-0.21213542j, 0.52331757+0.j ]]
>>> )
>>> print cardano_eqn(ham)
array([[-0.11143379-0.58863683j, -0.09067747-0.48219068j, 0.34276625-0.08686465j],
[ 0.14835519+0.47511473j, -0.18299305+0.40777481j, 0.31906300+0.82514223j],
[-0.62298966+0.07231745j, -0.61407815-0.42709603j, 0.03660313+0.30160428j]])
"""
if np.shape(ham) != (3, 3):
raise ValueError(
'Input matrix should be a square and dimension 3, '
'got\n{0}'.format(ham)
)
a = -np.trace(ham)
b = (0.5) * ((np.trace(ham))**2 - np.trace(np.dot(ham, ham)))
c = -linalg.det(ham)
Q = (1/9.) * (a**2 - 3*b)
R = (1/54.) * (2*a**3 - 9*a*b + 27*c)
theta = np.arccos(R / np.sqrt(Q**3))
E1 = -2 * np.sqrt(Q) * np.cos(theta/3.) - (1/3.)*a
E2 = -2 * np.sqrt(Q) * np.cos((theta - 2.*np.pi)/3.) - (1/3.)*a
E3 = -2 * np.sqrt(Q) * np.cos((theta + 2.*np.pi)/3.) - (1/3.)*a
A1 = ham[1][2] * (ham[0][0] - E1) - ham[1][0]*ham[0][2]
A2 = ham[1][2] * (ham[0][0] - E2) - ham[1][0]*ham[0][2]
A3 = ham[1][2] * (ham[0][0] - E3) - ham[1][0]*ham[0][2]
B1 = ham[2][0] * (ham[1][1] - E1) - ham[2][1]*ham[1][0]
B2 = ham[2][0] * (ham[1][1] - E2) - ham[2][1]*ham[1][0]
B3 = ham[2][0] * (ham[1][1] - E3) - ham[2][1]*ham[1][0]
C1 = ham[1][0] * (ham[2][2] - E1) - ham[1][2]*ham[2][0]
C2 = ham[1][0] * (ham[2][2] - E2) - ham[1][2]*ham[2][0]
C3 = ham[1][0] * (ham[2][2] - E3) - ham[1][2]*ham[2][0]
N1 = np.sqrt(abs(A1*B1)**2 + abs(A1*C1)**2 + abs(B1*C1)**2)
N2 = np.sqrt(abs(A2*B2)**2 + abs(A2*C2)**2 + abs(B2*C2)**2)
N3 = np.sqrt(abs(A3*B3)**2 + abs(A3*C3)**2 + abs(B3*C3)**2)
mm = np.array([
[np.conjugate(B1)*C1 / N1, np.conjugate(B2)*C2 / N2, np.conjugate(B3)*C3 / N3],
[A1*C1 / N1, A2*C2 / N2, A3*C3 / N3],
[A1*B1 / N1, A2*B2 / N2, A3*B3 / N3]
])
return mm
def normalise_fr(fr):
"""Normalise an input flavour combination to a flavour ratio.
Parameters
----------
fr : list, length = 3
flavour combination
Returns
----------
numpy ndarray flavour ratio
Examples
----------
>>> from fr import normalise_fr
>>> print normalise_fr((1, 2, 3))
array([ 0.16666667, 0.33333333, 0.5 ])
"""
return np.array(fr) / float(np.sum(fr))
NUFIT_U = angles_to_u((0.307, (1-0.02195)**2, 0.565, 3.97935))
"""NuFIT mixing matrix (s_12^2, c_13^4, s_23^2, dcp)"""
def params_to_BSMu(theta, dim, energy, mass_eigenvalues=MASS_EIGENVALUES,
nufit_u=NUFIT_U, no_bsm=False, fix_mixing=False,
fix_scale=False, scale=None, check_uni=True):
"""Construct the BSM mixing matrix from the BSM parameters.
Parameters
----------
theta : list, length > 3
BSM parameters
dim : int
Dimension of BSM physics
energy : float
Energy in GeV
mass_eigenvalues : list, length = 2
SM mass eigenvalues
nufit_u : numpy ndarray, dimension 3
SM NuFIT mixing matrix
no_bsm : bool
Turn off BSM behaviour
fix_mixing : bool
Fix the BSM mixing angles
fix_scale : bool
Fix the BSM scale
scale : float
Used with fix_scale - scale at which to fix
check_uni : bool
Check the resulting BSM mixing matrix is unitary
Returns
----------
unitary numpy ndarray of shape (3, 3)
Examples
----------
>>> from fr import params_to_BSMu
>>> print params_to_BSMu((0.2, 0.3, 0.5, 1.5, -20), dim=3, energy=1000)
array([[ 0.18658169 -6.34190523e-01j, -0.26460391 +2.01884200e-01j, 0.67247096 -9.86808417e-07j],
[-0.50419832 +2.14420570e-01j, -0.36013768 +5.44254868e-01j, 0.03700961 +5.22039894e-01j],
[-0.32561308 -3.95946524e-01j, 0.64294909 -2.23453580e-01j, 0.03700830 +5.22032403e-01j]])
"""
if np.shape(nufit_u) != (3, 3):
raise ValueError(
'Input matrix should be a square and dimension 3, '
'got\n{0}'.format(ham)
)
if fix_mixing:
s12_2, c13_4, s23_2, dcp, sc2 = 0.5, 1.0-1E-6, 0.5, 0., theta
elif fix_scale:
s12_2, c13_4, s23_2, dcp = theta
sc2 = np.log10(scale)
else:
s12_2, c13_4, s23_2, dcp, sc2 = theta
sc2 = np.power(10., sc2)
sc1 = sc2 / 100.
mass_matrix = np.array(
[[0, 0, 0], [0, mass_eigenvalues[0], 0], [0, 0, mass_eigenvalues[1]]]
)
sm_ham = (1./(2*energy))*np.dot(nufit_u, np.dot(mass_matrix, nufit_u.conj().T))
if no_bsm:
eg_vector = cardano_eqn(sm_ham)
else:
new_physics_u = angles_to_u((s12_2, c13_4, s23_2, dcp))
scale_matrix = np.array(
[[0, 0, 0], [0, sc1, 0], [0, 0, sc2]]
)
bsm_term = (energy**(dim-3)) * np.dot(new_physics_u, np.dot(scale_matrix, new_physics_u.conj().T))
bsm_ham = sm_ham + bsm_term
eg_vector = cardano_eqn(bsm_ham)
if check_uni:
tu = test_unitarity(eg_vector)
if not abs(np.trace(tu) - 3.) < 1e-5 or \
not abs(np.sum(tu) - 3.) < 1e-5:
raise AssertionError(
'Matrix is not unitary!\neg_vector\n{0}\ntest '
'u\n{1}'.format(eg_vector, tu)
)
return eg_vector
def test_unitarity(x, prnt=False):
"""Test the unitarity of a matrix.
Parameters
----------
x : numpy ndarray
Matrix to evaluate
prnt : bool
Print the result
Returns
----------
numpy ndarray
Examples
----------
>>> from fr import test_unitarity
>>> x = np.identity(3)
>>> print test_unitarity(x)
array([[ 1., 0., 0.],
[ 0., 1., 0.],
[ 0., 0., 1.]])
"""
f = abs(np.dot(x, x.conj().T))
if prnt:
print 'Unitarity test:\n{0}'.format(f)
return f
def u_to_fr(source_fr, matrix):
"""Compute the observed flavour ratio assuming decoherence.
Parameters
----------
source_fr : list, length = 3
Source flavour ratio components
matrix : numpy ndarray, dimension 3
Mixing matrix
Returns
----------
Measured flavour ratio
Examples
----------
>>> from fr import params_to_BSMu, u_to_fr
>>> print u_to_fr((1, 2, 0), params_to_BSMu((0.2, 0.3, 0.5, 1.5, -20), 3, 1000))
array([ 0.33740075, 0.33176584, 0.33083341])
"""
# TODO(shivesh): energy dependence
composition = np.einsum(
'ai, bi, a -> b', abs(matrix)**2, abs(matrix)**2, source_fr
)
ratio = composition / np.sum(source_fr)
return ratio
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